(4/49)(4-4x+x^2)-x=0

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Solution for (4/49)(4-4x+x^2)-x=0 equation: 


x in (-oo:+oo)

(4/49)*(x^2-(4*x)+4)-x = 0

(4/49)*(x^2-4*x+4)-x = 0

4/49*(x^2-4*x+4)-x = 0

4/49*(x^2-4*x+4)-x = 0

4/49*x^2-65/49*x+16/49 = 0

4/49*x^2-65/49*x+16/49 = 0

1/49*(4*x^2-65*x+16) = 0

4*x^2-65*x+16 = 0

DELTA = (-65)^2-(4*4*16)

DELTA = 3969

DELTA > 0

x = (3969^(1/2)+65)/(2*4) or x = (65-3969^(1/2))/(2*4)

x = 16 or x = 1/4

1/49*(x-1/4)*(x-16) = 0

1/49*(x-1/4)*(x-16) = 0

( x-1/4 )

x-1/4 = 0 // + 1/4

x = 1/4

( x-16 )

x-16 = 0 // + 16

x = 16

x in { 1/4, 16 }

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